Practicing Success
Three identical particles, each of mass m, are located in space at the vertices of an equilateral triangle of side length a. They are revolving in a circular orbital under mutual gravitational attraction. What is the acceleration of the centre of mass of a system comprising of any two particles. |
$\frac{\sqrt{3}}{2}\frac{Gm}{a^2}$ $\frac{3}{2}\frac{Gm}{a^2}$ $\frac{\sqrt{2}}{3}\frac{Gm}{a}$ $\frac{2}{3}\frac{Gm}{a}$ |
$\frac{\sqrt{3}}{2}\frac{Gm}{a^2}$ |
Consider our system to be made up of B and C. External force on this system is due to A. Net external force = 2F sin 60°. $=\sqrt{3}F=\frac{\sqrt{3}Gm^2}{a^2}$
$∴a_{cm}=\left(\frac{\sqrt{3}Gm^2}{a^2}\right)×\frac{1}{2m}$ $=\frac{\sqrt{3}}{2}\frac{Gm}{a^2}$ (towards the centre of the triangle) |